FOIL

1

107 x 49 = (107)·(49) = (100 + 7)·(40 + 9)
= 40x100 + 90x10 + ( )x10 + 63 =
= 4000 + 900 + ( )x10 + 63 = 5243

4

1

2

3

4

5

6

7

8

9

10

2 of 5

FirstOuterInnerLast

Level

How Many

FOIL method @			Example >>>	34 x 52 = (30 + 4)·(50 + 2)

First	(A + B)·(C + D) = AC + AD + BC + BD			= 30 x 50	= 1500
Outer	(A + B)·(C + D) = AC + AD + BC + BD			= 30 x 2	= 60
Inner	(A + B)·(C + D) = AC + AD + BC + BD			= 4 x 50	= 200
Last	(A + B)·(C + D) = AC + AD + BC + BD			= 4 x 2	= 8

					= 1768