FOIL

0

246 x 40 = (246)·(40) = (220 + 26)·(40 + )
= 88x100 + ( )x10 + 104x10 + 0 =
= 8800 + ( )x10 + 1040 + 0 = 9840

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FirstOuterInnerLast

Level

How Many

FOIL method @			Example >>>	34 x 52 = (30 + 4)·(50 + 2)

First	(A + B)·(C + D) = AC + AD + BC + BD			= 30 x 50	= 1500
Outer	(A + B)·(C + D) = AC + AD + BC + BD			= 30 x 2	= 60
Inner	(A + B)·(C + D) = AC + AD + BC + BD			= 4 x 50	= 200
Last	(A + B)·(C + D) = AC + AD + BC + BD			= 4 x 2	= 8

					= 1768